(2x^2+14x+28)/(x+4)=0

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Solution for (2x^2+14x+28)/(x+4)=0 equation: 



(2x^2+14x+28)/(x+4)=0



Domain of the equation: (x+4)!=0

We move all terms containing x to the left, all other terms to the right

x!=-4

x∈R



We multiply all the terms by the denominator


(2x^2+14x+28)=0

We get rid of parentheses

2x^2+14x+28=0

a = 2; b = 14; c = +28;
Δ = b2-4ac
Δ = 142-4·2·28
Δ = -28
Delta is less than zero, so there is no solution for the equation

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